点击回首页
我的浏览记录 | | 帮助?
当前位置:
首页>> 行业软件>> 在线考试系统>> 源文件浏览
[免费版 Free] WebForm,下载次数:418 次 | 关键字: 考试 办公 高校 竞赛 企事业单位

源码截图

源码目录树

;
当前路径:vendor/sebastian/diff/src/TimeEfficientLongestCommonSubsequenceCalculator.php
<?php declare(strict_types=1);
/*
 * This file is part of sebastian/diff.
 *
 * (c) Sebastian Bergmann <sebastian@phpunit.de>
 *
 * For the full copyright and license information, please view the LICENSE
 * file that was distributed with this source code.
 */

namespace SebastianBergmann\Diff;

final class TimeEfficientLongestCommonSubsequenceCalculator implements LongestCommonSubsequenceCalculator
{
    /**
     * {@inheritdoc}
     */
    public function calculate(array $from, array $to): array
    {
        $common     = [];
        $fromLength = \count($from);
        $toLength   = \count($to);
        $width      = $fromLength + 1;
        $matrix     = new \SplFixedArray($width * ($toLength + 1));

        for ($i = 0; $i <= $fromLength; ++$i) {
            $matrix[$i] = 0;
        }

        for ($j = 0; $j <= $toLength; ++$j) {
            $matrix[$j * $width] = 0;
        }

        for ($i = 1; $i <= $fromLength; ++$i) {
            for ($j = 1; $j <= $toLength; ++$j) {
                $o          = ($j * $width) + $i;
                $matrix[$o] = \max(
                    $matrix[$o - 1],
                    $matrix[$o - $width],
                    $from[$i - 1] === $to[$j - 1] ? $matrix[$o - $width - 1] + 1 : 0
                );
            }
        }

        $i = $fromLength;
        $j = $toLength;

        while ($i > 0 && $j > 0) {
            if ($from[$i - 1] === $to[$j - 1]) {
                $common[] = $from[$i - 1];
                --$i;
                --$j;
            } else {
                $o = ($j * $width) + $i;

                if ($matrix[$o - $width] > $matrix[$o - 1]) {
                    --$j;
                } else {
                    --$i;
                }
            }
        }

        return \array_reverse($common);
    }
}
关于我们 | 顾问团队 | 发展历程 | 联系我们 | 源码上传
联系电话(Tel):4008-010-151(免长途)
地址:北京市海淀区大恒科技大厦五层 邮编:100080
Floor 5th,Daheng Building,Zhongguancun,Beijing,China,100080
51Aspx.com 版权所有 CopyRight © 2006-2023. 京ICP备09089570号 | 京公网安备11010702000869号